From:	"OmniMeta" <meta AT abacom DOT com>
Newsgroups:	comp.os.msdos.djgpp
Subject:	Need help with class stuff
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Message-ID:	<TnNj3.667$3C2.65692@wagner.videotron.net>
Date:	Fri, 16 Jul 1999 17:25:23 -0300
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To:	djgpp AT delorie DOT com
DJ-Gateway:	from newsgroup comp.os.msdos.djgpp
Reply-To:	djgpp AT delorie DOT com

This program call a class function using a pointer to it.

Can someone please tell me why I get the warning :

tst.cpp(44) Warning:  converting from `void (Test::*)()' to `void (*)()'
tst.cpp(45) Warning:  converting from `void (Test::*)()' to `void (*)()'



Here is the little program :

#include <stdio.h> // printf
#include <conio.h> // clrscr getch

class Test
{
  void Print1();
  void Print2();

  public:

  void (*Action)(); // my pointer

  char select(char key);

}ClassTest;



int main()
{
  clrscr();
  printf("Type 1 or 2 : ");  fflush(stdout);

  do{}
  while( ClassTest.select(getch()) );

  ClassTest.Action();

  printf("\nPress a key to exit");
  fflush(stdout);

  getch();

 return 0;
}


char Test::select(char key)
{
  switch(key)
  {                                             // I get the warning at
   case '1': Action = &Print1; break; // this line
   case '2': Action = &Print2; break;      // And this line
    default : return 1;
  }
  return 0;
}

void Test::Print1()
{
 printf("\n\nHello !!!\nThis is what Print1 do.\n");
}


void Test::Print2()
{
 printf("\n\nHello !!!\nThis is what Print2 do.\n");
}

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