Date:	Sun, 1 Aug 1999 11:29:44 +0300 (IDT)
From:	Eli Zaretskii <eliz AT is DOT elta DOT co DOT il>
X-Sender:	eliz AT is
To:	Horst Kraemer <horst DOT kraemer AT snafu DOT de>
cc:	djgpp AT delorie DOT com
Subject:	Re: how about "more" random ?
In-Reply-To:	<37a166f1.169247036@news.snafu.de>
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Reply-To:	djgpp AT delorie DOT com
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On Fri, 30 Jul 1999, Horst Kraemer wrote:

> > > >         x = ((double) rand ()) * 100 / RAND_MAX;
> > > 
> > > Not exactly the correct method (IIRC), but close:
> > > 
> > > x = ((double) rand ()/RAND_MAX) * 100;
> > 
> > Care to explain what is the difference?
> 
> The difference is that both methods are wrong <g>
> 
> A correct formula is
> 
> 
>    int x = (double)rand()*100 / (RAND_MAX+1.0) ;

This will never generate 100, only numbers that are less that 100.  
Depending on the case in point, this might or might not be what
the original poster wanted.

> (With the incorrect RAND_MAX instead of RAND_MAX+1.0, the result will
> not be necessarily identical because the division by RAND_MAX is not a
> clean SHIFT of the 2-based exponent of the double value but a regular
> division).

Since the results are meant to be random, I don't see why this effect 
should matter, it simply introduces some more random bits near the LSB.

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