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From: | "Damian Yerrick" <NOSP AT Musenet@pineight.8m.com> |
Newsgroups: | comp.os.msdos.djgpp |
References: | <82cko6$sfk$1 AT imsp026 DOT netvigator DOT com> |
Subject: | Re: Why "c" is always zero?? |
Lines: | 81 |
Organization: | Pin Eight Software <http://pineight.8m.com/> |
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NNTP-Posting-Date: | Sun, 05 Dec 1999 05:59:32 GMT |
Distribution: | world |
Date: | Sun, 05 Dec 1999 05:59:32 GMT |
To: | djgpp AT delorie DOT com |
DJ-Gateway: | from newsgroup comp.os.msdos.djgpp |
Reply-To: | djgpp AT delorie DOT com |
"Jason Yip" <manman AT netteens DOT net> wrote in message news:82cko6$sfk$1 AT imsp026 DOT netvigator DOT com... >Can anyone tells me why the value of "c" is always equal to zero?? >How can I correct this? >Thanks a lot!! >#include <stdio.h> >float ftc(n) >int n; For one thing you're using old-style K&R function defs. float ftc(int n) >{ >float c, f; int i; Where do you assign the local variable 'f' a value? > for (i=0;i<=n;i++){ > c=5/9*(f-32); > } >return c; >} >main () int main() >{ >float c, f=0; int i=0; >do >{ >c=ftc(i); >printf("\t\t F=%.2f \t\t C=%.2f\n",f,c); >f++; >i++; >} while (i<=100); >} try this #include <stdio.h> float fahren2celsius(float fahren) { return 5/9 * (fahren - 32.); } int main() { int i; float fahren, celsius; for(i = 0; i < 212; i++) { fahren = i; celsius = fahren2celsius(fahren); printf("%f deg F = %f deg C\n", fahren, celsius); } return 0; } -- Damian Yerrick http://yerricde.tripod.com/ My .sig is too long to include in an e-mail or NG message. Go to http://www.rose-hulman.edu/~yerricde/sig.html to see it. qwtcc ehyrf
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