From:	Damian Yerrick <Bullcr_pd_yerrick AT hotmail DOT comRemoveBullcr_p>
Newsgroups:	comp.os.msdos.djgpp
Subject:	Re: How to convert mode to "pointer to array"?
Organization:	Pin Eight Software http://pineight.8m.com/
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References:	<39780BA1 DOT 7354F5D2 AT umist DOT ac DOT uk>
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NNTP-Posting-Date:	Fri, 21 Jul 2000 16:06:35 GMT
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Date:	Fri, 21 Jul 2000 16:06:35 GMT
To:	djgpp AT delorie DOT com
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Reply-To:	djgpp AT delorie DOT com

On Fri, 21 Jul 2000 09:36:49 +0100, Anthony Appleyard
<Anthony DOT Appleyard AT umist DOT ac DOT uk> wrote:

>I wrote a Gnu C++ program with this text in;-
>
>class atom{public: double x,y,z; char mat,vis; atom(){};
>    atom(xyz c,char m=0,char v=0){x=c.x; y=c.y; z=c.z; mat=m; vis=v;};
>
>atom((*C)[N+1][N+1])= /*HERE*/ malloc((N+1)*(N+1)*(N+1)*sizeof(atom));
>
>My Gnu C++ compiler accepts this, but moans that implicit conversion
>from void* to a pointer is non-ANSI, so I likely couldn't use that
>program text in my good old faithful Borland C++ 4.52 for Windows. To
>make this text ANSI, what should I insert at /*HERE*/ ?

In C++ you shouldn't be using malloc() and free() anyway, That's what
new and delete were designed for.

-- 
Damian Yerrick
"I refuse to listen to those who refuse to listen to reason."
See the whole sig: http://www.rose-hulman.edu/~yerricde/sig.html

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